x^2+6x=315

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Solution for x^2+6x=315 equation:



x^2+6x=315
We move all terms to the left:
x^2+6x-(315)=0
a = 1; b = 6; c = -315;
Δ = b2-4ac
Δ = 62-4·1·(-315)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-36}{2*1}=\frac{-42}{2} =-21 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+36}{2*1}=\frac{30}{2} =15 $

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